Answer:
Option A
Explanation:
Sum of diagonal entries of MTM is Σ a12
$\sum_1^9a_1^2=5$
Possibilities
I. 2,1,0,0,0,0,0,0,0 which gives $\frac{9!}{7!}$ matrices
II. 1,1,1,1,1,0,0,0,0 which gives $\frac{9!}{4!\times5!}$ matrices
Total matrices= $9\times8+9\times7\times2=198$